H=-16t^2-16t+0.6

Solution for H=-16t^2-16t+0.6 equation:

=-16H^2-16H+0.6

We move all terms to the left:

-(-16H^2-16H+0.6)=0

We get rid of parentheses

16H^2+16H-0.6=0

a = 16; b = 16; c = -0.6;
Δ = b2-4ac
Δ = 162-4·16·(-0.6)
Δ = 294.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-\sqrt{294.4}}{2*16}=\frac{-16-\sqrt{294.4}}{32}
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+\sqrt{294.4}}{2*16}=\frac{-16+\sqrt{294.4}}{32}
$